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authorNikolay Borisov2017-06-27 10:02:26 +0300
committerDavid Sterba2017-08-16 14:19:52 +0200
commitf148ef4d3a8feb2e30017050e3534a4d0646b769 (patch)
tree16c43b03201ce22e893589665bf50810a81cf20c /fs
parente5600fd6fc7d1924ff77681128a364e1dad4435b (diff)
btrfs: Be explicit about usage of min()
__btrfs_alloc_chunk contains code which boils down to: ndevs = min(ndevs, devs_max) It's conditional upon devs_max not being 0. However, it cannot really be 0 since it's always set to either BTRFS_MAX_DEVS_SYS_CHUNK or BTRFS_MAX_DEVS(fs_info->chunk_root). So eliminate the condition check and use min explicitly. This has no functional changes. Signed-off-by: Nikolay Borisov <nborisov@suse.com> Reviewed-by: David Sterba <dsterba@suse.com> Signed-off-by: David Sterba <dsterba@suse.com>
Diffstat (limited to 'fs')
-rw-r--r--fs/btrfs/volumes.c4
1 files changed, 2 insertions, 2 deletions
diff --git a/fs/btrfs/volumes.c b/fs/btrfs/volumes.c
index b011753ce8bb..f93ac3d7e997 100644
--- a/fs/btrfs/volumes.c
+++ b/fs/btrfs/volumes.c
@@ -4769,8 +4769,8 @@ static int __btrfs_alloc_chunk(struct btrfs_trans_handle *trans,
goto error;
}
- if (devs_max && ndevs > devs_max)
- ndevs = devs_max;
+ ndevs = min(ndevs, devs_max);
+
/*
* the primary goal is to maximize the number of stripes, so use as many
* devices as possible, even if the stripes are not maximum sized.