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authorStephen Warren2015-10-03 13:56:48 -0600
committerTom Rini2015-10-24 13:50:34 -0400
commit47b71644500f7dff768254570ff62c6e985e4bc3 (patch)
treeb8e23263e642ae4cdfdafadfd490f1e22d123ca4 /test
parent4a28274227d085d77d46709dc94ccc3d69610f53 (diff)
fs-test.sh: fix pre-requisite detection
In the following snippet: if [ ! -x `which $prereq` ]; then When $prereq does not exist, `which $prereq` evaluates to the empty string, which results in *no* argument being passed to the -x operator, which then evaluates to true, which is the equivalent of the prereq having been found. In order for this to fail as expected, we must pass an empty argument, which then causes -x to fail. Do this by wrapping the `` in quotes so there's always an argument to -x, even if the value of the argument is zero-length. Signed-off-by: Stephen Warren <swarren@wwwdotorg.org> Reviewed-by: Simon Glass <sjg@chromium.org> Tested-by: Simon Glass <sjg@chromium.org>
Diffstat (limited to 'test')
-rwxr-xr-xtest/fs/fs-test.sh2
1 files changed, 1 insertions, 1 deletions
diff --git a/test/fs/fs-test.sh b/test/fs/fs-test.sh
index 6f0a3455ed3..fc41c04c15e 100755
--- a/test/fs/fs-test.sh
+++ b/test/fs/fs-test.sh
@@ -58,7 +58,7 @@ GB2p5="${MOUNT_DIR}/${BIG_FILE}"
# Check if the prereq binaries exist, or exit
function check_prereq() {
for prereq in $PREREQ_BINS; do
- if [ ! -x `which $prereq` ]; then
+ if [ ! -x "`which $prereq`" ]; then
echo "Missing $prereq binary. Exiting!"
exit
fi